OpenFIPI 2.0
E74424
Текстовый файл состоит из заглавных букв латинского алфавита Q, R, W и цифр 1, 2, 4. Определите в прилагаемом файле максимальное количество идущих подряд символов, среди которых ни одна буква не стоит рядом с буквой, а цифра – с цифрой. Для выполнения этого задания следует написать программу. |
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Задание выполняется с использованием прилагаемых файлов.Ответы
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from re import * s=open('1.txt').readline() s=sub('[QRW](?=[QRW])','* ',s) s=sub('[124](?=[124])','* ',s) print(max(map(len,s.split())))
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3581 04R4Q4W1W1R4R1R1Q4Q4R1W4W2W4W4R1R2W1W4R4W4R4R4Q4W2R4W2W4R1W1W1R2W2Q4R1Q2Q4W1Q1Q4R2R1R1W1R4W4R1W2Q1Q2Q1W1Q2R2W4Q1W4W2Q1W4Q1R1Q2W1W2W1Q4R1Q1Q4Q2R1W4R4Q4Q4Q1R4W2Q1W1W2W1Q2R4W2R1Q2R2Q4R1R1Q4R4Q2Q1R2Q4W1R1Q1Q2R4W4W4Q4Q2Q1W4W1W4R4W1R2R1R4W4R2Q4R1R1W2R1R1Q2Q4Q4W2W4W4W2Q2Q1Q1R4Q4W1W1W1Q1W2R2Q1W4R2W1Q2R1W2Q4Q1Q1Q2R4Q4R2W1R4Q4Q2R1R4R1R4Q2R4R4Q2W4W2R1W2W4Q1W1W1Q1R2R2W4R1R4W2R2Q1Q4R4W2W1W4R1Q2Q1Q2Q1R4W4R4R1W2Q2R2Q2R4Q2Q2R4W1W2R2Q2R2Q1W4R2R4R4W4Q1Q4W4Q2Q4W4W2W1R4W4W2R1W1W2R2R4W1Q1Q2Q1R2R1Q1Q4W2Q2W4Q2W1W2R4R4R4R4W2R4W4R4R2R2W2R4W1W1W4Q1W1W1Q2Q2Q2R1R1W2W1W2R2Q2R1R2Q1W1Q1Q1Q2R1R4R2W1Q2W1Q2Q2Q1W4R1Q2R4Q2R4Q4R2R4Q4R1Q1R4W4Q2Q4Q2R4Q2W2W4R2Q4W2R2Q1W1R2Q1R2R4Q1Q1R1Q1W1Q2Q1W4W4R2Q1Q2W2W4R1Q4R2W1W4R4Q4W2R4Q2Q4Q1W2Q1Q2W2W1R4W2W4R4R1R4Q1Q2W2W1W1Q1W1W2Q2R1Q2R4Q2W1Q4W1R4W1W1Q2R4W2R2R2R4R1R2R1W2Q4R2Q2Q1W2Q4Q2Q2W2Q2W2W1W4W1R2R4W2R4W1Q2R1Q2R4Q1W2W4R4W1Q4Q2R4R4R1W1R2Q4R4Q2Q4Q1Q2Q1R2Q4R4W4W2R2W4R2Q1Q2W2W1W2W2W1R4R2Q4R4Q2W2Q1Q2W1R4Q2W1Q4W1R1Q4R1R2W4Q1R4W2W1R2R4W1R2Q2R2R2W1W1R2Q2Q1W2W1R2R4W4W1W1Q4Q2R2W1W2R1Q1R1Q1Q1W1R2Q4W4R1Q2Q1R1Q2W4Q2W1W4R4R1R2W2W1W1R2W2Q2W4Q4Q2R2Q4Q2W1W4W2W1R2W4Q2R1R4R1W4Q1Q2W4Q2W1R4Q2Q2R4R1R1R1R1W2W4W1W1Q1W4Q1R4W2Q4Q1Q2R2Q2R2W2W1R2R2W2W2W1R4R4Q4R2W4R4Q1W1W4R1Q2Q4W4Q2Q1Q1Q1W1R4W2R4R1Q1Q2W2Q4Q4R2R4R2Q4W2Q2W4R1Q4Q1W2Q2R4R4W2Q4R4Q1Q1Q1Q4Q2Q4R1Q4W4Q2Q2R4R2W1Q2Q4Q1W2Q1R4W4Q2R1R1R1W4Q2Q2Q4W1R4Q2R2W1Q1W2R1W2R2W4W2W1W2Q2Q4Q2R4Q2R4R1Q1W1W4Q2R1Q4R2W4Q1Q1R1Q2R2Q1R2R2R4W4W4Q2Q2R2Q2R1R2Q1Q4R1R1R4Q2W2W4W4R4R4R1R4R2W2Q1W1Q4R4Q2Q1R4W4W1Q4R2W2Q4Q2R1R4W1R4Q1Q2R4R4Q4Q2Q2Q2W1R1R2R2R2R4Q1R4W2W4Q2Q2R2R2W4R1R2W1R4W1W4W4R4R4R2R1W1W2R1W2R2W2R2Q4W1R4W1R1Q1W4Q4Q2W2W4R4R1R4W1W4W4W2Q2R1W2R4R1R1W2W1R1R1W2Q1Q1W2W4W2Q2R2R4W2R4Q1R1R1R1W2W1Q4R1Q1R2R2W4W4Q2W2Q4Q2R4Q2W1R2W4Q2Q4Q4Q2Q4W1R1Q4R2W4R1R4R1Q1Q1W1W1Q4R1Q1R4W1R2Q4R4R2R4Q4R2W1W2Q1W2Q4W2R4R4W4W4R1W2W4R1Q4W4R1Q4Q2R4R2W1Q4W2Q1Q1Q1Q4W1W1Q2Q2W4W2Q2Q2W2W1Q4R1R4Q2R1W4W2Q4W4W1Q2Q4Q2W2R4Q4R2W4Q2W4Q1Q1W4Q2R2Q4Q1R4R1R2W2R2R2Q2Q1Q2W2Q2R4Q1R2Q1W1R1W4W4R1W2R2W1Q2W1W4R1Q1W2R1Q4R4R1R4Q2Q2W1R4Q2R4R2Q2W4R4R4R1Q1R2R4Q2R2R1W1Q2Q1R4W4W4Q1R4R2Q1W1R2Q2Q4W4Q4R1W4Q4Q2W1R2Q2R1W2W4Q1W1W4Q4Q2W4Q2W2Q4R1R4R1R1R4Q1Q1W2W1Q1Q1Q4R2R4R1R1Q1Q1Q4Q2Q1Q2Q2W1R4Q2Q1R2Q4R4Q1R1W1R2Q4W4Q2R4W2W2W1R4R2R2R4W4R1Q1R1R1R2Q1R2W2Q4Q2R1R4R4R1Q4R2W1R1W4Q2Q4R1W1Q1Q2Q1R2Q1W2R1Q4Q1Q4R1W4W1Q2W2Q1Q4W1R1Q1R1Q1Q2Q1R2R1Q2Q2Q4Q4W1W4Q1R1R2W4W4R1W1Q4Q4Q2Q4R4W2W4R2Q4Q2Q2Q4R2W4W4R1R2W4Q2R4R2W2Q4R1R1W2R4R1W2Q4R2W1Q4Q2W4R2Q2R4Q4W2R4Q4W2Q4W1W2R4W4R2W4R2R4R2R2R4Q1R1R1W1Q4Q4R4Q1Q1W4W4Q2R1Q2Q1W2Q2Q4W4R2Q4W2Q2W2Q2R2Q1W4W4R4R1Q2W4W1W1Q2Q2R4W4R1W2Q2W2Q2W2W1R1Q4W1R2R2R2W2W1W1Q4W2W2W1W4Q2Q2Q1W1R2Q2R1Q2Q2W2Q2W4R4W1R2Q1R2R1W2R2Q4Q4W4Q2W1Q2W2W4W4R4Q4W1W4R2Q4W2R2R1R2R4Q2R1R1Q2R1W1W1W2Q2Q4Q4R4W1W2R2W2Q2Q4W2W4R4R1W4R1R1R2Q4R2Q1R1Q4Q1R2R1W1W4Q4W1R4R2W4Q4W4R4Q2Q1Q2W4Q2R4Q1W2W2Q2R1Q4W2R1R1Q2R1Q1R4R2R1Q1Q4Q1R1R1R4Q1W4R2W2Q2Q2W4W1W1W4R1W4Q2R1Q1W4W4R1W4Q1W1W1R1W2R4R2W1R4W4W4Q2R1Q1W1W2Q4W4Q4R4Q1Q1R4R2R1R4R1W4Q4W1W2R1Q4W1W1W1W2W2Q2Q4Q4Q4Q1W1R2Q4W1W2R1Q4W4R2Q4Q2W2Q1W1W4Q4W2Q2Q1W4Q1R2R4Q4W2Q1W2Q1Q2Q4W1W1W2W1R2W2R4R4W1W2W1Q2W4R1W1Q4Q1W4Q2Q1Q4W2W2Q1Q2R4Q1W4R1R1W2R1Q4Q2R2W2W4R1W4Q1Q2Q2R4Q4R1W1W2Q1Q4Q4R2R2W2Q2Q1R4Q2W2Q4Q1W4W2R1Q4W4Q2W2W2W1W2W1W1Q1W1W2R1W1W4W4Q1R4Q4Q4Q4R2W2W2W4Q4R1R4R1W1Q2W4R1Q4W1R4R1R2R4R1W2Q2R4R4R2R2R2Q2W1W4W4W1R4W1R4Q4R2Q1Q2Q4W4R1W2Q4Q4R4Q4R2W4R1Q1R2R1Q4Q1W2R1W1Q4W2Q1R4R1Q1W2W2W4W4Q4R2Q1R2W2W2W1Q1W4W2W2Q4R4W4R2Q2Q1Q4Q2R1Q4Q4Q2Q2R2Q2Q4R2R4R2W1W1R2Q4R4R4Q1W4Q2R4Q2R1W4W2R1W1Q4Q4Q2W4R1R2R1Q4R2W1R4R2R4R1R2W4Q1Q4W1Q2W4Q2W1R2R2Q1R4R1Q1Q2Q4Q1R4Q1Q2W2W2R1Q4W4Q1Q1Q4R2W4W2W2Q4W1Q2Q4Q1R1Q4Q4R2W2Q1Q1Q4W1W1W1Q2R2W4W4R4R4W1Q1W2W2W1R2W2R2W2R1W4Q4R4W1R4W2Q1Q1R2Q1Q4Q2Q1Q2R1Q2Q4R4W4W1W4R1W1W4Q1Q2Q1Q1W1W2W4Q1Q2R2W4R1R4W4Q1Q1Q1R4Q2Q4R2R1R2W4Q2R4W1R1Q4Q1R4Q4R4W2R1R2W2Q2Q2R1Q1R1Q4R4Q2W4R1W4R4R4W2R2R4Q4Q1W2Q2Q1W f = open('1_24.txt').read() s = list(f) qwr = 'QWR' ch = '124' c =0 m=0 p='' pk='' for i in range(len(s)-1): if not (s[i] in qwr and s[i+1] in qwr) and not (s[i] in ch and s[i+1] in ch): c+=1 p= str(p) + str(s[i]) else: if c>m: pk=p m=c c=0 p=0 print(m-1,pk)